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Question

The real part of coshα+iβis


A

coshαcosβ

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B

cosαcosβ

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C

cosαcoshβ

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D

sinαsinhβ

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Solution

The correct option is A

coshαcosβ


Explanation for the correct option:

Given expression is coshα+iβ let us expand the identity and then we will find the real part of it so,

coshα+iβ=cosh(α)+cosh(iβ)+sinh(α)sinh(iβ)coshα+iβ=cosh(α)cos(β)+isinh(α)sin(β)

So, we see that real part of given expression is coshαcosβ

Hence, the correct option is (A)


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