Evaluate sec2A+1sec2A=
secA
2secA
sec2A
2sec2A
Solve the function:
We know, secA=1cosA⋯1
With the help of equation (1), we can rewrite the question as:
sec2A+1sec2A=1cos2A+11cos2A=1+cos2Acos2A1cos2A=2cos2Acos2A1cos2A[∵cos2A=2cos2A-1]=2cos2A=2sec2A[∵cos2A=1sec2A]
Hence, the correct answer is option (D).