sin2ix+cosh2x=
1
-1
2cosh2x
coshx
Explanation for the correct answer:
Simplifying the given expression:
We know that, sinix=isinhx
Also,
sin2(ix)=(isinhx)2=–sinh2x[∵i2=-1]
Now,
⇒sin2ix+cosh2x⇒cosh2x–sinh2x[∵cosh2x–sinh2x=1]⇒1
Therefore, the correct answer is option (A).
Prove that (x+1)(x+1-i)(x-1+i)(x-1-i)=x4+4