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Question

sin2ix+cosh2x=


A

1

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B

-1

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C

2cosh2x

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D

coshx

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Solution

The correct option is A

1


Explanation for the correct answer:

Simplifying the given expression:

We know that, sinix=isinhx

Also,

sin2(ix)=(isinhx)2=sinh2x[i2=-1]

Now,

sin2ix+cosh2xcosh2xsinh2x[cosh2xsinh2x=1]1

Therefore, the correct answer is option (A).


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