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Question

(sin4θ) can be written as:


A

4sinθ12sin2θ1sin2θ

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B

2sinθcosθsin2θ

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C

4sinθ6sin3θ

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D

None of these

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Solution

The correct option is A

4sinθ12sin2θ1sin2θ


Explanation for correct option:

Simplifying the equations using trigonometric identities:

Given expression is: (sin4θ)

Expanding the expression:

sin4θ=sin2(2θ)

Using the formula sin2A=2sinAcosA we get:

sin4θ=2sin2θcos2θ

Using the formula cos2θ=12sin2θ we get:

sin4θ=2(2sinθcosθ)(12sin2θ)=4sinθ(12sin2θ)(cosθ)

Using the identity sin2A+cos2A=1 we get:

sin4θ=4sinθ12sin2θ1sin2θ

Therefore, the correct answer is option (A).


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