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Question

Tangent and normal are drawn at P16,16 on the parabola y2=16x, which intersect the axis of the parabola at Aand Brespectively. If C is the center of the circle through the points P,A,and Band CPB=θ, then a value of tanθis


A

3

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B

43

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C

12

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D

2

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Solution

The correct option is D

2


Explanation for the correct option:

Finding the value of tanθ:

Given parabola, y2=16x.

Then, dydx=162y=8y.

So, the slope of the tangent to the given parabola at P(16,16)=dydx(16,16)=8y(16,16)=816=12.

and the slope of the normal to the given parabola at

P(16,16)=-dxdy(16,16)=-y8(16,16)=-168=-2.

Then the equation of the tangent at P(16,16) is

y-16=12x-162y-32=x-16x-2y+16=0

and the equation of the normal at P(16,16) is

y-16=-2x-162x+y-48=0

The tangent and normal intersect the axis of the parabola at A(-16,0)andB(24,0)respectively

Since, C is the center of the circle through the points A,PandB and APPB, So, AB is the diameter of the circle and hence C is the mid-point of the line segment AB and hence the coordinates of C would be -16+242,0=4,0.

Now, the slope of the line segment PC=m1=16-016-4=1612=43.

Again, the slope of the line segment PB=m2=16-016-24=16-8=-2.

Hence

tanθ=m1-m21+m1m2=43--21+43×-2=103-53=10-5=2

Therefore, the correct answer is option (D).


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