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Question

The angle between the lines represented by the equation x2+y2sinθ+2xy=0 is


A

θ

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B

θ2

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C

π2-θ

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D

π2-θ2

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Solution

The correct option is C

π2-θ


Explanation for correct answer:

Finding the angle between the lines:

Given the equation x2+y2sinθ+2xy=0

x2sinθ+2xy+y2sinθ=0

Now comparing the given equation with the general form of an equation of pair of lines ax2+2hxy+by2=0

We get a=sinθ,b=sinθ,2h=2h=1

Finding the angle between the two lines using the formula

tanβ=2h2-aba+b

Substituting a=sinθ ,b=sinθ and h=1in the above equation. we get

tanβ=21-sinθsinθsinθ+sinθ=21-sinθ22sinθ=1-sin2θsinθ

Substituting 1-sin2θ=cos2θ

tanβ=cos2θsinθ=cosθsinθ=cotθ

Removing the modulus

tan(β)=cotθ=tan(90-θ)

Apply tan-1 on both sides

tan-1tan(β)=tan-1tan(90-θ)β=90-θ

Therefore, the angle between the two lines is 90-θ

Hence, option (C) is the correct answer


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