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Question

The area of a circle and the area of a regular polygon of n sides of the perimeter equal to that of that circle are in the ratio


A

tanπn:πn

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B

cosπn:πn

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C

sinπn:πn

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D

cotπn:πn

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Solution

The correct option is A

tanπn:πn


Explanation for correct answer:

Step 1: Finding A1 and A2

It is given that, the perimeter of a circle is equal to the perimeter of a polygon.

Let 'r‘ is the radius of a circle and ’a' be the side of a regular polygon.

Therefore,

2πr=na (’n' is the number of sides of a polygon)

a=2πrn

Let the area of a circle is denoted by ‘A1

Therefore, A1=πr2i

Let 'A2' represent the area of a regular polygon, and the area of a polygon is calculated by using the formula given below.

A2=14n×a2×cotπn(ii)

Substituting the value of a=2πrn in equation (ii) we get,

A2=14n×2πrn2×cotπn=π2rn2×cotπn(iii)

Step 2: Determining the ratio of the two areas

By Dividing equation (i) by equation (iii) we get,

A1A2=πr2π2rn2×cotπn=nπ×cotπn=nπ×tanπn

A1:A2=tanπn:πn

Hence, option (A) is the correct answer.


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