The condition f(x)=x3+px2+qx+r,x∈R to have no extreme value, is
p2<3q
2p2<q
p2<14q
p2>3q
Explanation for the correct option:
Finding the condition:
Given Equation f(x)=x3+px2+qx+r,x∈R
To have no extreme value, f'(x)≠0
f'(x)=3x2+2px+q≠0
And also, the discriminant should be less than 0,
Hence, D<0
⇒4p2–4×3×q<0⇒4p2–12q<0⇒p2<3q
Hence, option (A) is the correct answer.