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Question

The distance traveled s by an accelerated particle of mass M is given by the following relation (in MKS units) s=6t+3t2. The velocity of the particle after 2s in the corresponding unit.


A

6

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B

12

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C

18

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D

24

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Solution

The correct option is C

18


Step 1: Given data

Distance travelled by particle, s=6t+3t2

Time t=2sec

Step 2: Compute the velocity

It is understood that the rate of change of distance with respect to time is known as velocity.

It means, v=dsdt

So,

ddts=ddt6t+3t2dsdt=6+6tv=6+6tvt=2=6+6×2vt=2=18m/sec

The velocity of the particle after 2s is, vt=2=18m/sec.

Hence, option (C) is the correct answer.


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