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Question

The electron gain enthalpy (in kJ/mol) of Fluorine, Chlorine, Bromine, and Iodine, respectively, are:


A

-333, -325, -349 and -296

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B

-333, -349, -325 and -296

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C

-296, -325, -333 and -349

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D

-349, -333, -325 and -296

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Solution

The correct option is B

-333, -349, -325 and -296


Explanation of the correct option:

The correct answer is option B:

  1. Fluorine (F) has a smaller size than Chlorine (Cl) and thus has a less negative electron gain enthalpy.
  2. In F, the extra electron will be added to the 2p orbital, but in Cl, it will go into the 3p orbital.
  3. A 2p orbital will be more compact because electron-electron repulsion will be greater since it takes up less space than a 3p orbital.
  4. Hence in the event of a F, the incoming electron would be accepted with substantially less.
  5. Therefore, F's electron gain enthalpy is lower than Cl's.
  6. Electron gain enthalpy falls when you move from Cl to Iodine (I) due to a drop in electronegativity.
  7. Cl>F>Br>I is the order of electron gain enthalpy.
  8. So, -333, -349, -325, and -296 are the respective electron gain enthalpies of Fluorine, Chlorine, Bromine, and Iodine.

Explanation of the correct options:

Option A:

  1. The correct order of electron gain enthalpy is Cl>F>Br>I.
  2. Thus, -333, -325, -349, and -296 are not the respective electron gain enthalpies of Fluorine, Chlorine, Bromine, and Iodine.

Option C:

  1. The correct order of electron gain enthalpy is Cl>F>Br>I.
  2. Thus, -296, -325, -333, and -349 are not the respective electron gain enthalpies of Fluorine, Chlorine, Bromine, and Iodine.

Option D:

  1. The correct order of electron gain enthalpy is Cl>F>Br>I.
  2. Thus, -349, -333, -325, and -296 are not the respective electron gain enthalpies of Fluorine, Chlorine, Bromine, and Iodine.

Hence, option B is correct, i.e., -333, -349, -325 and -296.


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