The equation of the tangent to the curve - y - -2x - 1- e-2 -1 - x nbsp- at the point of its maximum- is- y - 1 - 0- x - 1 - 0- x - y - 1 - 0- x - y - 1 - 0-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Local Maxima

The equation ...

Question

The equation of the tangent to the curve $y = (2 x - 1) e^{2 (1 - x)}$ at the point of its maximum, is

y - 1 = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x - 1 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x + y - 1 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x - y + 1 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

The normal at the point (1, 1) on the curve 2y + x² = 3 is

(A) x + y = 0 (B) x − y = 0

y = (2 x - 1) e^{2 (1 - x)}

x^{2} + y^{2} - 2 x + 4 y = 0

Join BYJU'S Learning Program