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Question

The figure formed by four pointsi^+j^+k^,2i^+3j^,3i^+5j^-2k^,k^-j^ is a?


A

Parallelogram

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B

Rectangle

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C

Trapezium

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D

Square

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Solution

The correct option is C

Trapezium


Explanation for the correct option

The given points are i^+j^+k^,2i^+3j^,3i^+5j^-2k^,k^-j^

AB=2i^+3j^-i^+j^+k^=i^+2j^-k^AB=12+22+-12=6BC=3i^+5j^-2k^-2i^+3j^=i^+2j^-2k^BC=12+22+-22=9=3CD=k^-j^-3i^+5j^-2k^=-3i^-6j^+3k^CD=-32+-62+32=54DA=i^+j^+k^-k^-j^=i^+2j^DA=12+22+02=5ABCD

So the given figure has only two parallel sides and the length of the sides are not equal

So, the points make a trapezium

Hence, option (C) is the correct answer.


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