The function [sin(x+α)][sin(x+β)] has no maximum or minimum if
β–ɑ=Kπ
β–ɑ≠Kπ
β–ɑ=2Kπ
Noneofthese
Explanation for correct option
⇒f(x)=[sin(x+α)][sin(x+β)]
⇒f'(x)=sin(x+β)·cos(x+α)–sin(x+α)·cos(x+β)sin2(x+β)
On expanding each and every term we get,
⇒f'(x)=sin(β-α)sin2(x+β)
For no maxima and minima,
⇒f'(x)≠0
⇒sin(β-α)sin2(x+β)≠0
So, from the above equation
sin(β-α)≠0
⇒β-α≠Kπ [where, K=0,1,2,3,....... ]
Hence, option B is correct.
The function f(x) = ex