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Question

The function [sin(x+α)][sin(x+β)] has no maximum or minimum if


A

βɑ=Kπ

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B

βɑKπ

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C

βɑ=2Kπ

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D

Noneofthese

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Solution

The correct option is B

βɑKπ


Explanation for correct option

f(x)=[sin(x+α)][sin(x+β)]

f'(x)=sin(x+β)·cos(x+α)sin(x+α)·cos(x+β)sin2(x+β)

On expanding each and every term we get,

f'(x)=sin(β-α)sin2(x+β)

For no maxima and minima,

f'(x)0

sin(β-α)sin2(x+β)0

So, from the above equation

sin(β-α)0

β-αKπ [where, K=0,1,2,3,....... ]

Hence, option B is correct.


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