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Question

The greatest value of 2x+3y+4z+5u for possible values of x,y,zand u such that 4x+9y+16z+25u=720 is


A

105

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B

125

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C

245

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D

365

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Solution

The correct option is C

245


The explanation for the correct answer.

Find the greatest value:

Given: 4x+9y+16z+25u=720=k (constant)

Here m=12,n=14(0<m<1)

The greatest value of 2x+3y+4z+5u=41-(½)(720)12

[Because the greatest value of a1m+a2+..ann=n1-mkm where a1=a2=..an and a1+a2..+an=k= constant, 0<m<1]

=4×720=2×125=245

Hence, option (c) is the correct answer.


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