Explanation for the correct option:∫e^e^e^x·e^e^x·e^x dxLet e^e^e^x=z⇒e^e^e^x·e^e^x·e^x dx = dz0ex0ex⇒∫ dz = z+C = e^e^e^x+CHence, option (C) is correct. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Quadratic Equations

The integral ...

Question

The integral $\int e^{e^{e^{x}}} \cdot e^{e^{x}} \cdot e^{x} d x = . . . + C$ is equal to

$e^{e^{x}}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{1}{2} e^{2} e^{e^{x}}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$e^{e^{e^{x}}}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{1}{2} e^{e^{x}}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$e^{e^{e^{x}}}$

Explanation for the correct option:
$\int e^{e^{e^{x}}} \cdot e^{e^{x}} \cdot e^{x} d x$
Let $e^{e^{e^{x}}} = z$
$\Rightarrow e^{e^{e^{x}}} \cdot e^{e^{x}} \cdot e^{x} d x = d z \Rightarrow \int d z = z + C = e^{e^{e^{x}}} + C$
Hence, option (C) is correct.

Suggest Corrections

Similar questions

Q. The integral

\int cos ({log}_{e} x) d x

is equal to: (where

C

is a constant of integration)

Q. The value of integral

\int {cosec}^{3} x d x

is equal to

(

where

C

is integration constant

)

\int {tan}^{6} x d x

is equal to
(where

C

is integration constant)

Q. The value of integral

\int \sqrt{\frac{x - 2}{x - 3}} d x

is equal to
(Where

C

is integration constant)

Q. The integral

\int \frac{d x}{(1 + \sqrt{x}) \sqrt{x - x^{2}}}

is equal to (where C is a constant of integration):

Join BYJU'S Learning Program

The integral ∫eeex·eex·exdx=...+C is equal to

The correct option is C eeexExplanation for the correct option:∫eeex·eex·exdxLet eeex=z⇒eeex·eex·exdx=dz⇒∫dz=z+C=eeex+CHence, option (C) is correct.

The integral $\int e^{e^{e^{x}}} \cdot e^{e^{x}} \cdot e^{x} d x = . . . + C$ is equal to

The correct option is C
$e^{e^{e^{x}}}$

Explanation for the correct option:
$\int e^{e^{e^{x}}} \cdot e^{e^{x}} \cdot e^{x} d x$
Let $e^{e^{e^{x}}} = z$
$\Rightarrow e^{e^{e^{x}}} \cdot e^{e^{x}} \cdot e^{x} d x = d z \Rightarrow \int d z = z + C = e^{e^{e^{x}}} + C$
Hence, option (C) is correct.