The line 3x-y+5+λ2x-3y-4=0 will be parallel to y-axis, if λ=
13
-32
-13
32
Calculate the value of λ.
The given equation is 3x-y+5+λ2x-3y-4=0
⇒3x-y+5+2λx-3λy-4λ=0⇒x3+2λ-y1+3λ+5-4λ=0
Here slope of the line is m=3+2λ1+3λ
Since the line is parallel to y axis, slope is undefined.
⇒1+3λ=0⇒λ=-13
Hence option C is correct.