Question

The minimum frequency ${\varsigma }_{min}$ of continuous $X$-rays is related to the applied pot. diff. $V$ as

• A. $V_{min}\propto V$
• B. $V_{min}\propto V^{1/2}$
• C. $V_{min}\propto V^{-3}$
• D. $V_{min}\propto V^4$

Answer 1

The correct option is A

$V_{min}\propto V$

Step 1: Given data:

The minimum frequency of continuous $X$-rays$={\varsigma }_{min}$

Applied potential difference$=V$

Step 2: Finding the relation

The energy of photon during $X$-ray emission is,

$E=h{V}_{min}$($E=$Energy, $V_{min}=$Minimum frequency)

Again this energy is,

$E=eV$ ($e=$Charge of the electron)

Thus we can conclude that,

$V\propto V_{min}$

Thus, the minimum frequency$V_{min}$ of continuous $X$-rays is related to the applied pot. diff. $V$ as$V\propto V_{min}$.

Hence, option A is the correct answer.