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Question

The minimum frequency ςmin of continuous X-rays is related to the applied pot. diff. V as


A

VminV

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B

VminV1/2

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C

VminV-3

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D

VminV4

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Solution

The correct option is A

VminV


Step 1: Given data:

The minimum frequency of continuous X-rays=ςmin

Applied potential difference=V

Step 2: Finding the relation

The energy of photon during X-ray emission is,

E=hVmin(E=Energy, Vmin=Minimum frequency)

Again this energy is,

E=eV (e=Charge of the electron)

Thus we can conclude that,

VVmin

Thus, the minimum frequencyVmin of continuous X-rays is related to the applied pot. diff. V asVVmin.

Hence, option A is the correct answer.


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