The negation of (p∨~q)∧q is
(~p∨q)∧~q
(p∧~q)∨q
~p∧q∨~q
(~p∧~q)∧~q
Explanation for the correct option:
Given: (p∨~q)∧q
We know that the negation of A is given by ~A and the De’ Morgan’s laws says ~(a∨b)=~a∧~b.
So the negation of (p∨~q)∧q is,
~(p∨~q)∧q=~(p∨~q)∨~q∵~(a∧b)=~a∨~b=~p∧~~q∨~q∵~(a∨b)=~a∧~b=~p∧q∨~q∵~(~a)=a
Therefore, the negation of (p∨~q)∧q is ~p∧q∨~q.
Hence, option C is the correct option.