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Question

The number of groups that can be made from 5 different green balls, 4 different blue balls and 3 different red balls, if at least 1 green and 1 blue ball is to be included?


A

3700

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B

3720

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C

4340

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D

None of these

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Solution

The correct option is B

3720


Explanation for the correct option:

Find the required number of groups.

Three groups of 5 different green balls, 4 different blue balls, and 3 different red balls are given.

The total number of groups that can be formed out of given groups are 212.

The total number of groups having no blue balls is 28.

The total number of groups having no green balls is 27.

The total number of groups having no green balls and no blue balls is 23.

So, the total number of groups with at least 1 green and 1 blue balls is given by 212-(27+28-23)=3720.

Therefore, The number of groups that can be made from 5 different green balls, 4 different blue balls, and 3 different red balls, if at least 1 green and 1 blue balls are to be included is 3720.

Hence, option B is the correct option.


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