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Question

The number of turns in primary and secondary coils of a transformer is 50 and 200, respectively. If the current in the primary coil is 4A, then the current in the secondary coil is


A

1A

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B

2A

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C

4A

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D

5A

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Solution

The correct option is A

1A


Step 1: Given Data

Number of turns in the primary coil NP=50

Number of turns in the secondary coil NS=200

Current in the primary coil IP=4A

Let Is be the current in the secondary coil.

Step 2: Formula Used

NPNS=ISIP

Step 3: Calculate Current in Secondary Coil

We know that in a transformer,

NPNS=ISIPIS=NPNS×IP

Upon substituting the values we get,

IS=50200×4=1A

Hence, the current in the secondary coil is 1A and therefore the correct answer is option (A).


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