The period of sinhx2 is
2πi
cot(hx)
4πi
cothx
Explanation for the correct option:
Compute the period of the given function.
We know that the period of sinhx is 2πi,
So, the period of sine hyperbolic for half-angle, i.e., sinhx2 =2(2πi)=4πi
Thus, the period of sinhx2 is 4πi.
Hence, option (C) is the correct answer.