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Question

The probabilities of three mutually exclusive events are 23,14 and 16. The statements is


A

True

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B

Wrong

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C

Could be either

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D

Do not know

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Solution

The correct option is B

Wrong


Explanation for the correct option:

Given that the probabilities of 3 mutually exclusive events are 23,14 and 16

Let us assume that A,B and C are the three events.

Then, P(A+B+C)=P(A)+P(B)+P(C)

=23+14+16

=1312 which is greater than 1

Hence, the given statement is wrong.

Hence, the correct answer is option (B), Wrong.


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