The proposition p→~(p∧q) is equivalent to
~p∨(~q)
~p∧q
q
~p∨q
Explanation for the correct option:
Given proposition, p→~(p∧q)
=~(p∧~q)→~p∨q=p→(p~∨q)=~p∨(~p∨q)=~p∨q
Hence, the correct option is D, ~p∨q