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Question

The reaction of following with H3N3B3Cl3(A) withinLiBH4 in tetrahydrofuran gives inorganic benzene (B), Then (A) reacts with (C) formingH3N3B3Me3. Compounds (B) and (C) are


A

Borazine and MeBr

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B

Boron nitride and MeBr

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C

Borazine and MeMgBr

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D

Diborane and MeMgBr

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Solution

The correct option is C

Borazine and MeMgBr


The explanation for the correct option

C. Borazine and MeMgBr

  • H3N3B3Cl3(s)+LiBH4(s)T.H.FIntetrahydrofuraneB3N3H6(s)+LiCl(s)+BCl3(s)(A)(InorganicBenzene)(B)
  • B3N3H3Cl3(s)+3MeMgBr(s)B3N3H3CH33(s)+3MgBrCl(s)(A)(C)

Hence option (C) is correct.,Compounds (B) and (C) are Borazine and MeMgBr.


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