The set of admissible values ofx such that2x+32x-9<0 is
(-∞,–32)∪(92,ɑ)
(-∞,0)∪(92,ɑ)
(-32,0)
(0,92)
-32,92
The explanation for the correct answer.
Compute the required set:
2x+32x-9<0
2x+3<0 and 2x–9>0
or 2x+3>0 and 2x–9<0 and x≠92
⇒x<–32 and x>92
or x>–32 and x<92 and x≠92
⇒x∈-32,92
Hence, option E is the correct answer.