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Question

The solution of the differential equation dydx+sin2y=0 is


A

y+2cosy=c

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B

y-2siny=c

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C

x=coty+c

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D

y=cotx+c

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Solution

The correct option is C

x=coty+c


Explanation for the correct option

Given: dydx+sin2y=0

dydx=-sin2ydy-sin2y=dx

integrating both sides

-csc2ydy=dxcoty+c=x

Hence, option C is correct.


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