The straight lines 4ax+3by+c=0,where a+b+c=0, are concurrent, at the point
(4,3)
14,13
12,13
None of these
Explanation for the correct option:
Given: 4ax+3by+c=0...(i)
a+b+c=0...(ii)
⇒c=-(a+b)
Put cin (i)
⇒4ax+3by–a–b=0⇒a(4x-1)+b(3y-1)=0⇒(4x-1)+ba3y-1=0⇒(4x-1)=0,(3y-1)=0⇒x=14,y=13
Hence, the correct option is option B