The unit vector along i^+j^ is:
k^
i^+j^
i^+j^2
The explanation for the correct answer:-
Option (C)
Step 1: Calculating the unit vector along i^+j^,
we know R^=R⇀R
R^= It is the unit vector of R⇀
R is the magnitude of R⇀
R⇀=i^+j^
R=12+12= 2
R^=R⇀R=12i^+12j^=i^+j^2
Hence, option C is the correct answer.