A- B- and C are three isomers molecular formula C8H11N that gave the following result-A and Cdiazotisation-P-QiiOxidationKMnO4-H-iHydrolysis-RProduct of A-S Product of CR has a lower boiling point than S- BC6H5SO2Cl-a alkali-insoluble productWhat are A- B- and C-

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Standard XII

Chemistry

Uses of Slaked Lime

A, B, and C a...

Question

A, B, and C are three isomers (molecular formula $C_{8} H_{11} N$ ) that gave the following result.
A and C $\overset{diazotisation}{\to}$ P+Q $\to_{(ii) Oxidation ({KMnO}_{4} + H^{+})}^{(i) Hydrolysis}$ R(Product of A)+S (Product of C)
R has a lower boiling point than S, B $\overset{C_{6} H_{5} {SO}_{2} Cl}{\to}$ a alkali-insoluble product
What are A, B, and C?

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Solution

The correct option is B

Explanation for the correct options
(B)
Using all the three isomers of the $C_{8} H_{11} N$ compound, the following reactions takes place:
Final Answer: Hence option (B) is correct., are A ,B, and C.

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A, B, and C are three isomers (molecular formula C8H11N) that gave the following result.A and C→diazotisationP+Q→(ii)OxidationKMnO4+H+(i)HydrolysisR(Product of A)+S (Product of C)R has a lower boiling point than S, B→C6H5SO2Cla alkali-insoluble productWhat are A, B, and C?

The correct option is B Explanation for the correct options(B)Using all the three isomers of the C8H11N compound, the following reactions takes place:Final Answer: Hence option (B) is correct., are A ,B, and C.

The correct option is B

Explanation for the correct options
(B)
Using all the three isomers of the $C_{8} H_{11} N$ compound, the following reactions takes place:
Final Answer: Hence option (B) is correct., are A ,B, and C.