Question

What will be the mass of $5$ moles of ${\mathrm{SO}}_2$?

Answer 1

Given moles of Sulphur dioxide $\left({\mathrm{SO}}_2\right)$$=5\mathrm{mol}$

Step 1: Formula used:

• Moles are defined as the ratio of a given mass over the molar mass of the species.
• Mathematically it is represented as follows:
  $\mathrm{Moles}\left(\mathrm{n}\right)=\frac{\mathrm{Mass}}{\mathrm{Molar}\mathrm{mass}}$-----------------------(I)

Step 2: Calculating the molar mass of Sulphur dioxide:

• The atomic mass of Sulphur is $32\mathrm{g}$.
• The atomic mass of Oxygen is $16\mathrm{g}$.
• Thus, the molar mass of ${\mathrm{SO}}_2=(32+2\times 16)\mathrm{g}{\mathrm{mol}}^{-1}=64\mathrm{g}{\mathrm{mol}}^{-1}$

Step 3: Calculating the mass of $5$moles of ${\mathrm{SO}}_2$

• Applying equation (I), we get
• $\mathrm{Mass}\mathrm{of}{\mathrm{SO}}_2=\mathrm{Moles}\mathrm{of}{\mathrm{SO}}_2\times \mathrm{Molar}\mathrm{mass}\mathrm{of}{\mathrm{SO}}_2=5\mathrm{mol}\times 64\mathrm{g}{\mathrm{mol}}^{-1}$
• So, $\mathrm{Mass}\mathrm{of}{\mathrm{SO}}_2=320\mathrm{g}$.

Hence, the mass of $5$ mol of ${\mathrm{SO}}_2$ is $320\mathrm{g}.$