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Question

Which equation is incorrect?


A

λm°(NaBr)λm°(NaCl)=λm°(KBr)λm°(KCl)

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B

λm°(NaBr)λm°(NaI)=λm°(KBr)λm°(NaBr)

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C

λm°(KCl)λm°(NaCl)=λm°(KBr)λm°(NaBr)

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D

λm°(H2O)=λm°(HCl)+λm°(NaOH)λm°(NaBr)

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Solution

The correct option is B

λm°(NaBr)λm°(NaI)=λm°(KBr)λm°(NaBr)


Explanation for the correct options:

Option B is the correct answer.

Kohlrauch's Law: The limiting molar conductivity (λm°) for strong and weak electrolyte can be determined by using Kohlrauch's law : "the limiting molar conductivity of an electrolyte can be represented as the sum of the individual contributions of the anion and cation of the electrolyte."

λm°(NaBr)λm°(NaI)=λm°(KBr)λm°(NaBr)

λm°(NaBr)λm°(NaI)=λm°(KBr)λm°(NaBr)L.H.S.λm°(Na+)+λm°(Br-)λm°(Na+)-λm°(I-)=λm°(Br-)-λm°(I-)R.H.Sλm°(K+)+λm°(Br-)λm°(Na+)-λm°(Br-)=λm°(K+)λm°(Na+)

Therefore, option B is correct answer.


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