Question

Which of the following compounds contain bonds between the same type of atoms?

$N_2{O}_4,B_3{N}_{3}H6,H_2{S}_2{O}_3,N_{2}O,H_2{S}_2{O}_8,B_2{H}_6$

Answer 1

${\mathrm{N}}_2{\mathrm{O}}_4$ contains a bond between the same type of atom. The bond is between two nitrogen atoms.

${\mathrm{B}}_3{\mathrm{N}}_3{\mathrm{H}}_6$ do not contain bonds between the same type of atoms. It contains B-N, B-H, and N-H bonds.

${\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_3$ contains one $\mathrm{S}=\mathrm{S}$bond.

${\mathrm{N}}_2\mathrm{O}$ contains the same type of bond between nitrogen atoms.

${\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_8$ contains two bonds between the same type of atoms that is sulfur atoms and oxygen atoms.

${\mathrm{B}}_2{\mathrm{H}}_6$ contains no bond of the same type of atoms.

1. Hence, 4 molecules i.e.,${\mathrm{N}}_2{\mathrm{O}}_4$, ${\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_3$, ${\mathrm{N}}_2\mathrm{O}$, and ${\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_8$ contain the bond of the same type of atoms.