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Question

Which of the following is not correct for an ideal gas as per first low of thermodynamics?


  1. Adiabatic ΔU=w

  2. Isothermal q=-w

  3. cyclic q=-w

  4. Isochoric ΔU=q

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Solution

The correct option is A

Adiabatic ΔU=w


Explanation for the correct option:-

  1. For Adiabatic process, q=0 ΔU=w
  2. In the given option the value of W is given in negative but in the correct formula as per first law of thermodynamic the value of W is in positive.
  3. From 1st Law, U=q+W
  4. Inadiabatic,q=0,Therefore,U=W

Hence, Option A is the correct option.


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