The correct option is
C Compound II becomes more acidic, when it has a -NO2 substituent.
Explanation for correct option:
A. The acidity of compound I is due to delocalization in the conjugate base.
- When at least three p orbitals overlap, this is called conjugation.
- Let's examine this molecule and determine whether or not three p orbitals can overlap anywhere:
- Because double bonds form on p-orbitals, they are the simplest way to recognize a p-orbital.
- Option A is correct
B. The conjugate base of compound IV is aromatic.
- Due to the conjugation of the p orbitals and the presence of delocalized p electrons, aromatic compounds contain a 'ring current' and are hence diamagnetic.
- The ring with eight pi electrons cannot be aromatic,
- Hence the conjugate base with six pi electrons is aromatic and should be more stable.
- This suggests that cyclopentadiene is more acidic than cycloheptatriene
- Option B is correct
C. Compound II becomes more acidic, when it has a substituent.
- In the ortho or meta position, deactivating substituents like the nitro group strip the aromatic ring and the carboxylate anion of their electron density.
- As a result, the conjugate base's negative charge is stabilized, raising the acidity of the carboxylic acid.
- Option C is correct
Explanation for incorrect option:
D. The acidity of compounds follows the order
- Triphenylmethane (I) is acidic because resonance has stabilized the conjugate base.
- Because the conjugate base of cyclopentadiene (IV) is aromatic, it is acidic.
- Due to the nitro group's electron withdrawing nature, nitrobenzene is more acidic than benzene.
- By -I effect, it will stabilize the conjugate base of benzene.
- Option is incorrect then the order of acidity is
Hence the correct statements are:
A. The acidity of compound I is due to delocalization in the conjugate base.
B. The conjugate base of compound IV is aromatic.
C. Compound II becomes more acidic, when it has a -NO2 substituent.