Question
\(15x^2+26x+8=0\)
Solution
Quadratic Formula Method
1
\( \text{Compare } 15 x^{2} + 26 x + 8 = 0 \text{ with the standard quadratic equation } ax^2 +bx+c = 0 \text{ and find the values of a, b, and c } \)
\( a = 15 \text{ , } b = 26 \text{ , } c = 8 \)
2
Calculate the value of the discriminant (D)
\( D = 196 \)
3
Determine the nature of the roots
The roots are real and distinct
4
\( \text{ Apply the quadratic formula } \)
\(x = \frac{-26 \pm 14}{30}\)
5
\( \text{Find the roots of given quadratic equation } 15 x^{2} + 26 x + 8 = 0 \)
\( \text{The roots are } - \frac{4}{3} \text{ and } - \frac{2}{5} \)
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