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Byju's Answer
Standard X
Chemistry
Direct Combination
0.001 mole of...
Question
0.001 mole of Cr(NH3)5(NO3)SO4 was passed through cation exchanger and the acid coming out of it required 20 ml 0.1M NaOH for neutralisation. Hence the complex is ?
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Similar questions
Q.
0.001 mol of
C
o
(
N
H
3
)
5
(
N
O
3
)
(
S
O
4
)
was passed through a cation exchanger and the acid coming out of its required 20 ml of 0.1 M NaOH for neutralisation. Hence, the complex is
:
Q.
0.001
mole of
[
C
o
(
N
H
3
)
5
(
N
O
3
)
(
S
O
4
)
]
was passed through a cation exchanger and the acid coming out of it required
20
ml of
0.1
M
N
a
O
H
for neutralisation. Thus, the complex is :
Q.
0.0012 mole of
C
r
C
l
3
⋅
6
H
2
O
was passed through a cation exchange resin and acid coming out of it required 28.5 mL of 0.125 M
N
a
O
H
. Hence, the formula of the complex is:
Q.
A solution containing
0.319
g
of complex
C
r
C
l
3
.6
H
2
O
was passed through cation exchanger and the solution given out was neutralised by
28.5
m
L
of
0.125
M
N
a
O
H
. What is the correct formula of complex ?
Q.
100 ml of sample of hard water is passed through a column of the cation exchange resin
H
2
R
. The water coming out of the column requires 20 ml of 0.025 M
N
a
O
H
for the titration. The hardness of water expressed as ppm of
C
a
2
+
ion is:
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