Question

$0.001M$ ${NH}_{4}Cl$ aqueous solution has pH:

• A. $6.127$
• B. $7.126$
• C. $2.167$
• D. $1.267$

Answer 1

The correct option is A $6.127$

${NH}_{4}Cl$ is salt formed from weak base ${NH}_{4}OH$ and strong acid $HCl$.

$\therefore$ $pH=\frac{1}{2}[pKw-pKa-logc]$

$=\frac{1}{2}[14-4.7447-log(0.001\left)\right]$

$=6.127$