0-01 m aqueous solution of K 3 - Fe CN 6 - freezes at -0-0 62 -C- what is the apparent percentage of dissociation - k f H 2 O -1-86K kg moI -1

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Standard XII

Chemistry

Solubility Product

0.01 m aqueou...

Question

0.01 m aqueous solution of $K_{3} [F e {(C N)}_{6}]$ freezes at $- 0.0 62^{\circ} C$ , what is the apparent percentage of dissociation ?
$(k_{f} (H_{2} O) = 1.86 K k g {m o I}^{- 1})$

83 %

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78 %

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74 %

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87 %

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Solution

The correct option is B 78 %
see from the formula
dT = i K m
u get I as 3.33
v know that I = 1 + ( n-1) a
n = 4
u get a as 0.778
78%

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Similar questions

A 0.01m aqueous solution of $K_{3} [F e (C N)_{6}]$ was found to freeze at $- {0.062}^{\circ} C$ . If Kf for water is ${1.86}^{\circ} C$ /molal then the apparent percentage of dissociation is:

Q. A

0.01 m

aqueous solution of

K_{3} [F e (C N)_{6}]

freezes at

- {0.062}^{\circ} C

. What is the apparent percentage of dissociation?

[K_{f}

for water

= 1.8]

[Note : Write the value to the nearest integer]

Q. A

0.15

molal solution of

K_{4} [F e (C N)_{6}]

in water freezes at

- {0.65}^{\circ} C

. What is the apparent percentage of dissociation of this compound in this solution?

[K_{f}

for water

= {1.86}^{\circ} C m o l^{- 1}]

An aqueous solution freezes at $- {2.55}^{\circ} C$ . What is its boiling point?

$(K_{b} H_{2} O = 0.52 K / m; K_{f} H_{2} O = 1.86 K / m)$

Q. An aqueous solution freezes at

- {2.55}^{\circ} C

. What will be the boiling point of solution?

(K_{b} (H_{2} O) = 0.52 K / m; K_{f} (H_{2} O) = 1.86 k / m)

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0.01 m aqueous solution of K3[Fe(CN)6] freezes at −0.062∘C, what is the apparent percentage of dissociation ?(kf(H2O)=1.86KkgmoI−1)

The correct option is B 78 %see from the formula dT = i K m u get I as 3.33 v know that I = 1 + ( n-1) a n = 4 u get a as 0.77878%

0.01 m aqueous solution of $K_{3} [F e {(C N)}_{6}]$ freezes at $- 0.0 62^{\circ} C$ , what is the apparent percentage of dissociation ?
$(k_{f} (H_{2} O) = 1.86 K k g {m o I}^{- 1})$

The correct option is B 78 %
see from the formula
dT = i K m
u get I as 3.33
v know that I = 1 + ( n-1) a
n = 4
u get a as 0.778
78%