Question

$0.02M$ monobasic acid dissociates $2\%$ hence, $pH$ of the solution is:

• A. $0.3979$
• B. $1.3979$
• C. $1.699$
• D. $3.3979$

Answer 1

Answer: (D)

$3.3979$

$\left[H^{+}\right]=\alpha .C=\frac{2}{100}\times .02;\left[H^{+}\right]=4\times {10}^{-4}M$

$pH=-\log \left[H^{+}\right]$

$pH=3.3979$