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Standard XII

Chemistry

1900's Physics and Wave

0.024g of Mg ...

Question

0.024g of Mg on burning in oxygen gave 0.40g of MgO. What is equivalent mass of Mg?

13 g

e q u i v^{- 1}

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12 g

e q u i v^{- 1}

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10 g

e q u i v^{- 1}

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11.5 g

e q u i v^{- 1}

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Solution

The correct option is C 10 g $e q u i v^{- 1}$
$2 M g + O_{2} ⟶ 2 M g O$
$0.024$ $0.40$ $g$
Mass of oxygen used $⟹ 0.40 - 0.024 = 0.376$ $g$
As, $0.024$ $g$ of $M g - 0.0370$ $g$ of Oxygen
$10.21$ $g$ of $M g - 16$ $g$ of Oxygen
Equivalent mass of $M g = 10.21$ $g$

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0.024g of Mg on burning in oxygen gave 0.40g of MgO. What is equivalent mass of Mg?

The correct option is C 10 g equiv−12Mg+O2⟶2MgO0.024 0.40 gMass of oxygen used ⟹0.40−0.024=0.376 gAs, 0.024 g of Mg−0.0370 g of Oxygen10.21 g of Mg−16 g of OxygenEquivalent mass of Mg=10.21 g

The correct option is C 10 g $e q u i v^{- 1}$
$2 M g + O_{2} ⟶ 2 M g O$
$0.024$ $0.40$ $g$
Mass of oxygen used $⟹ 0.40 - 0.024 = 0.376$ $g$
As, $0.024$ $g$ of $M g - 0.0370$ $g$ of Oxygen
$10.21$ $g$ of $M g - 16$ $g$ of Oxygen
Equivalent mass of $M g = 10.21$ $g$