Question

$0.08kg$ of a substance is heated from ${30}^{o}C$ to ${130}^{o}C$, when $2000$ calories of energy is supplied to it. Calculate the specific heat capacity of the substance in $\left(a\right)$ calories $\left(b\right)$ joules.

Answer 1

(a)$H=mc\Delta t$

$c=\frac{H}{m\Delta t}$

$\Rightarrow c=\frac{2000}{80\times 100}=0.25cal/gK$

(b)1 cal = 4.184 J

$\Rightarrow c=0.25\times 4.184=1.046J/gK$