Question

0.0833 mol of a carbohydrate of empirical formula $C{H}_{2}O$ contain $1\text{g}$ of hydrogen. The molecular formula of the carbohydrate is:

• A. $C_5{H}_{10}{O}_5$
• B. $C_6{H}_{12}{O}_6$
• C. $C_{12}{H}_{12}{O}_{11}$
• D. $C_3{H}_4{O}_3$

Answer 1

The correct option is B $C_6{H}_{12}{O}_6$

0.0833 mol of carbohydrate has 1 mol of $H$
So, 1 mol of carbohydrate = $\frac{1\times 1}{0.0833}$ mol of $H$ = 12 mol of $H$
The compound can be either $C_6{H}_{12}{O}_6$ or $C_{12}{H}_{12}{O}_{11}$
Since the question has provided the empirical formula of the carbohydrate to be $C{H}_{2}O$, option (b) will the correct answer.