Question

$0.092$ g of an organic compound containing phosphorous gave $0.111$ g of $M{g}_2{P}_2{O}_7$ by usual analysis. Calculate the percentage of the phosphorous in the organic compound.

• A. $45.95$%
• B. $29.65$%
• C. $37.32$%
• D. $33.7$%

Answer 1

Answer: (D)

$33.7$%

$\%$ of Phosphorus $=\frac{62}{222}\times \frac{MassofM{g}_2{P}_2{O}_7}{Massoforganiccompound}\times 100$

$⟹\%$ of Phosphorus $=\frac{62}{222}\times \frac{0.111}{0.092}\times 100$

$⟹\%$ of Phosphorus $0.279\times 1.20\times 100$

$⟹\%$ of Phosphorus $=33.7\%$ (approx.)