Question

0.1 formal solution of NaCl is found to be isotonic with $1.10\%$ solution of urea. Calculate the apparent degree of ionization of NaCl.

• A. 0.80
• B. 0.81
• C. 0.82
• D. 0.83

Answer 1

The correct option is D 0.83

${\pi }_{NaCl}={\pi }_{urea}=n\times \frac{1}{V}\times RT$

$\pi =\frac{n}{V}\times RT$

$i\times 0.1\times RT=\frac{1.1}{60\times 0.1}\times RT$

$i=1.83$

$\alpha =\frac{i-1}{n-1}=\frac{1.83-1}{2-1}=0.83$

$\alpha =0.83$