Question

# 0.1 formal solution of NaCl is found to be isotonic with $$1.10\%$$ solution of urea. Calculate the apparent degree of ionization of NaCl.

A
0.80
B
0.81
C
0.82
D
0.83

Solution

## The correct option is D 0.83$$\pi_{NaCl}=\pi_{urea}=n \times \dfrac{1}{V} \times RT$$$$\pi=\dfrac{n}{V} \times RT$$$$i \times 0.1 \times RT=\dfrac{1.1}{60 \times 0.1} \times RT$$$$i=1.83$$$$\alpha=\dfrac{i-1}{n-1}=\dfrac{1.83-1}{2-1}=0.83$$$$\alpha=0.83$$Chemistry

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