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Ideal Gas Equation

0.1 g of a so...

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0.1 g of a solution containing Na2CO3 and NaHCO3 requires 10 ml, of 0.01 N HCl.neutralization using phenophthalein .wt % of Na2C03 in solutions is:(a) 25 (b) 32 (c) 50 (d) None of thes

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50 m L

of a solution of

N a_{2} C O_{3}

N a H C O_{3}

17.5 m L

0.1 M H_{2} S O_{4}

for neutralisation using phenolphthalein as indicator. Methyl orange is then added when further

25 m L

0.2 M H_{2} S O_{4}

was required. Calculate the weight of

N a_{2} C O_{3}

N a H C O_{3}

respectively in the solution.

Q. A solution contains

N a_{2} C O_{3}

N a H C O_{3}

10 mL

of this solution required

2.5 mL

0.1 M H_{2} S O_{4}

for neutralization using phenolphthalein as an indicator. Methyl orange is then added when a further

2.5 mL

0.2 M H_{2} S O_{4}

was required. The amount of

N a_{2} C O_{3}

N a H C O_{3}

respectively, in 1 litre of solution is:

Q. A solution contains

N a_{2} C O_{3}

N a H C O_{3}, 10 m L

of this solution required

2.5 m L

0.1 M H_{2} S O_{4}

for neutralisation using phenolphthalein indicator. Methyl orange is added after first end point, further titration required

2.5 m L

0.2 M H_{2} S O_{4}

. The amount of

N a_{2} C O_{3}

N a H C O_{3}

1

litre of the solution is:

Q. A solution contained

N a_{2} C O_{3}

N a H C O_{3}

15 m l

of the solution required

5 m l

\frac{N}{10} H C l

for neutralization using phenolphthalein as an indicator. Addition of methyl orange required a further

15 m l

of the acid for neutralization. The amount of

N a_{2} C O_{3}

present in the solution is:

Q. Given two mixtures: (A)

N a O H

N a_{2} C O_{3}

(B)

N a H C O_{3}

N a_{2} C O_{3}

.

100

mL of mixture (A) required

a

b

1 M

H C l

in separate titration using phenolphthalein and methyl orange indicators respectively while

100

mL of mixture (B) required

x

y

H C l

solution is separate titration using the same indicators.

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