$0.1 g r a m m o l e$ of urea is dissolved in $100 g$ of water. The molality of the solution is:

1 M

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0.01 M

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0.001 M

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1.0 M

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Solution

The correct option is B $1 M$
Moles of urea $= 0.1 m o l e$
Mass of Solvent $(H_{2} O) = 100 g = 0.1 k g$
Molality $= \frac{m o l e s (s o l u t e)}{m a s s (s o l v e n t i n k g)}$
$= \frac{0.1}{0.1} = 1 m o l a l$
Hence, option $A$ is correct.

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