Question

0.1 M of $HA$ is titrated with 0.1 M $NaOH$, calculate the $pH$ at end point. Given, $K_a\left(HA\right)=5\times {10}^{-6}$ and $\alpha <<1$.

Answer 1

It is a Selection of weak acid and strong base

type buffer solution

$PW=Pka+log\left[\frac{salt}{acid}\right]$

Here concentration of both of things are equal so

log 1 is equal to = 0

$PH=Pka$

$=-log5\times {10}^{-6}$

$=6-0.6989$

$=5.301$