0.1 M solution of a solute has a water potential of

-2.2 bars

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0 bar

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22.4 bars

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+2.3 bars

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Solution

The correct option is A -2.2 bars
The water potential can be calculated by the formula nRT, where n is number of moles, R the standard gas constant and T is standard temperature in Kelvin. Substituting the values of R (0.08314 lit bar per kelvin per more ), T (273 kelvin), n (0.1 moles) we get water potential 2.2 bars. As water potential of all solutions is always negative the correct answer will be -2.2 bars.

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