0-1 M solution of KI reacts with excess of H 2 SO 4 and KIO 3 solutions acccording to equation 5 I - IO 3-6 H - 3 I 2-3 H 2 O which ofthe following statement is correct-A- 400 ml of the KI solution react with 0-004 mole KIO 3B- 400 ml of the KI solution react with 0-006 mole H 2 SO 4C- 0-5 litre of the KI solution produced 0-005 mole of I 2D- Equivalent weight of KIO 3 is eual to Molecular Weight -5

The correct options are D Equivalent weight of KIO_3 is eual to ( Molecular Weight5 )5I^ +IO_3^ +6H^+→ 3I_2+3H_2O as we know by this equation that 5 moles of K ...

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Standard XII

Chemistry

Molarity

0.1 M solutio...

Question

$0.1 M$ solution of KI reacts with excess of $H_{2} S O_{4}$ and $K I O_{3}$ solutions acccording to equation $5 I^{-} + I O_{3}^{-} + 6 H^{+} \to 3 I_{2} + 3 H_{2} O$ which of the following statement is correct?

400 ml of the K I solution react with 0.004 mole K I O_{3}

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400 ml of the K I solution react with 0.006 mole H_{2} S O_{4}

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0.5 litre of the K I solution produced 0.005 mole of I_{2}

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Equivalent weight of K I O_{3} is eual to (\frac{Molecular Weight}{5})

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Solution

The correct option is D $Equivalent weight of K I O_{3} is eual to (\frac{Molecular Weight}{5})$
$5 I^{-} + I O_{3}^{-} + 6 H^{+} \to 3 I_{2} + 3 H_{2} O$
as we know by this equation that $5 m o l e s$ of $K I$ react with $1 m o l e o f K I O_{3}$ so
$\frac{moles of KI used}{Moles of K I O_{3}} = 5$
(A) as we know
$M = \frac{n \times 1000}{Volume of solution(in mL)}$
$m o l e (n) o f K I = \frac{0.1 \times 400}{1000} = 0.04$
$m o l e (n) o f K I O_{3} = \frac{0.04}{5} = 0.008$
(C) $m o l e (n) o f K I = \frac{0.1 \times 500}{1000} = 0.05$
$m o l e (n) o f K I O_{3} = \frac{0.05}{5} = 0.01$
valancy factor of $K I O_{3} = 5$
$∴ Equivalent weight of K I O_{3} = \frac{molecular weight of K I O_{3}}{5}$

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Molarity

Standard XII Chemistry

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0.1 M solution of KI reacts with excess of H2SO4 and KIO3 solutions acccording to equation 5I−+IO−3+6H+→3I2+3H2O which of the following statement is correct?

$0.1 M$ solution of KI reacts with excess of $H_{2} S O_{4}$ and $K I O_{3}$ solutions acccording to equation $5 I^{-} + I O_{3}^{-} + 6 H^{+} \to 3 I_{2} + 3 H_{2} O$ which of the following statement is correct?